Physics · OCR H556 · Topic 3.5

Newton's laws of motion and momentum

Newton's laws of motion, collisions.

  • 2 sub-topics
  • Taught in Year 12
  • 43 practice questions
  • 2 animated lessons
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What the specification says

Every sub-topic OCR can examine in this topic, with its reference number from the official specification. The Y12 and Y13 tags show when each sub-topic is usually taught.

  1. 3.5.1Newton's laws of motionY12
  2. 3.5.2CollisionsY12

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Easy, medium and hard questions from this topic, each with a worked solutions and the mark for every step. All 43 questions in this topic, free, no account needed.

Mechanics

Easy

Newton's second law · Year 12 · 1 mark

  1. A car of mass 1500 kg has a driving force of 4500 N and a total resistive force of 300 N. What is its acceleration?
    (1)

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  1. Use the resultant force: a=F−Rma = \dfrac{F - R}{m}.B: 2.80 m s−22.80\ \mathrm{m\,s^{-2}}

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Mechanics

Medium

Free-body diagrams · Year 12 · 6 marks

A person of mass 60 kg stands on bathroom scales in a lift. The lift is moving upwards and slowing down at 1.0 m s⁻².
  1. (a)
    Draw a free-body force diagram for the person.
    (2)
  2. (b)
    Find the reading on the scales in newtons.
    (3)
  3. (c)
    Explain why the person feels heavier (or lighter) than normal.
    (1)

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Part (a)2 marks

  1. Weight mg acting downwards from the centre of mass.
  2. Normal contact force R from the scales acting upwards.

Part (b)3 marks

  1. Newton's second law, taking up as positive.R−mg=maR - mg = ma
  2. R=60(9.81−1.0)R = 60(9.81 - 1.0)
  3. R=529 NR = 529\ \mathrm{N}

Part (c)1 mark

  1. The contact force is less than their weight (589 N).

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Mechanics

Hard

Recoil · Year 12 · 2 marks

A gun of mass 2 kg fires a bullet of mass 0.01 kg at 400 m s⁻¹.
  1. Find the recoil speed of the gun.
    (2)

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  1. 0=0.01(400)−2V0 = 0.01(400) - 2V
  2. V=2.00 m s−1V = 2.00\ \mathrm{m\,s^{-1}}

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