Physics · OCR H556 · Topic 6.3

Electromagnetism

Magnetic fields, motion of charged particles, electromagnetism.

  • 4 sub-topics
  • Taught in Year 13
  • 74 practice questions
  • 4 animated lessons
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What the specification says

Every sub-topic OCR can examine in this topic, with its reference number from the official specification. The Y12 and Y13 tags show when each sub-topic is usually taught.

  1. 6.3.1Magnetic fieldsY13
  2. 6.3.2Motion of charged particlesY13
  3. 6.3.3Electromagnetism: flux, flux linkage and inductionY13
  4. 6.3.3Electromagnetism: transformersY13

Try 3 questions

Easy, medium and hard questions from this topic, each with a worked solutions and the mark for every step. All 74 questions in this topic, free, no account needed.

Electric and magnetic fields

Not needed for Year 12Easy

Force on a current-carrying wire · Year 13 · 1 mark

  1. A wire carrying a current of 2.0 A lies at right angles to a magnetic field of flux density 0.12 T. A length of 5.0 cm of the wire is in the field. What is the force on the wire?
    (1)

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  1. F=BILF = BIL, with the length in metres.C: 0.0120 N0.0120\ \mathrm{N}

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  • A
  • B
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Electric and magnetic fields

Not needed for Year 12Medium

Magnetic flux and flux linkage · Year 13 · 4 marks

A coil of 500 turns and area 0.0100.010 m² is in a uniform magnetic field of 0.12 T. The normal to the coil is at 60° to the field.
  1. (a)
    Calculate the flux through the coil and the flux linkage.
    (3)
  2. (b)
    State the orientation of the coil that gives zero flux linkage.
    (1)

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Part (a)3 marks

  1. ϕ=BAcos⁡θ\phi = BA\cos\theta
  2. ϕ\phi=6.00×10−4 Wb{}= 6.00 \times 10^{-4}\ \mathrm{Wb}
  3. Nϕ=0.300 Wb turnsN\phi = 0.300\ \mathrm{Wb\,turns}

Part (b)1 mark

  1. With its plane parallel to the field.

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Electric and magnetic fields

Not needed for Year 12Hard

Faraday's law · Year 13 · 4 marks

A coil of 500 turns and area 0.00200.0020 m² is perpendicular to a magnetic field, which falls uniformly from 0.4 T to 0.0 T in 0.05 s.
  1. (a)
    State Faraday's law.
    (1)
  2. (b)
    Calculate the magnitude of the induced e.m.f.
    (3)

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Part (a)1 mark

  1. The induced e.m.f. equals the rate of change of flux linkage.

Part (b)3 marks

  1. Δ(Nϕ)\Delta(N\phi)=500×0.0020×(0.4−0.0){}= 500 \times 0.0020 \times (0.4 - 0.0)
  2. ε\varepsilon=Δ(Nϕ)Δt{}= \frac{\Delta(N\phi)}{\Delta t}
  3. ε=8.00 V\varepsilon = 8.00\ \mathrm{V}

Total4

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  • B
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