Physics · Pearson Edexcel 9PH0 · Topic 2

Mechanics

Motion, suvat equations, vectors, projectiles, Newton's laws, momentum, moments, work, energy and power.

  • 22 sub-topics
  • Taught in Year 12
  • 265 practice questions
  • 22 animated lessons
Practice questions (265) Lessons Worksheets All Edexcel Physics topics

What the specification says

Every sub-topic Pearson Edexcel can examine in this topic, with its reference number from the official specification. The Y12 and Y13 tags show when each sub-topic is usually taught.

  1. 9Equations for uniformly accelerated motionY12
  2. 10Displacement–time, velocity–time and acceleration–time graphsY12
  3. 11Quantities from gradients and areas of graphsY12
  4. 12Scalar and vector quantitiesY12
  5. 13Resolving a vector into perpendicular componentsY12
  6. 14Resultant of coplanar vectorsY12
  7. 15Independence of vertical and horizontal motion of a projectileY12
  8. 16Free-body force diagramsY12
  9. 17Newton's first and second laws and terminal velocityY12
  10. 18Gravitational field strength and weight, W = mgY12
  11. 19CP1: Determine the acceleration of a freely-falling objectY12
  12. 20Newton's third lawY12
  13. 21Momentum, p = mvY12
  14. 22Conservation of linear momentum in one dimensionY12
  15. 23Moment of a forceY12
  16. 24Centre of gravity and the principle of momentsY12
  17. 25Work doneY12
  18. 26Kinetic energyY12
  19. 27Gravitational potential energyY12
  20. 28Conservation of energyY12
  21. 29PowerY12
  22. 30EfficiencyY12

Try 3 questions

Easy, medium and hard questions from this topic, each with a worked solutions and the mark for every step. All 265 questions in this topic, free, no account needed.

Mechanics

Easy

Scalars and vectors · Year 12 · 7 marks

A walker goes 9 m due east and then 12 m due north, taking 50 s in total.
  1. (a)
    Explain the difference between a scalar and a vector quantity, giving an example of each from this situation.
    (2)
  2. (b)
    Find the walker's displacement from the start.
    (3)
  3. (c)
    Find the average speed and the magnitude of the average velocity.
    (2)

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Part (a)2 marks

  1. A scalar has magnitude only (e.g. distance); a vector has magnitude and direction (e.g. displacement).
  2. Distance travelled and time are scalars; displacement and velocity are vectors.

Part (b)3 marks

  1. 92+122\sqrt{9^2 + 12^2}
  2. s=15.0 ms = 15.0\ \mathrm{m}
  3. tan θ = east/north.on a bearing of 037°

Part (c)2 marks

  1. speed\text{speed}=0.420 m s−1{}= 0.420\ \mathrm{m\,s^{-1}}
  2. ∣vˉ∣|\bar{v}|=0.300 m s−1{}= 0.300\ \mathrm{m\,s^{-1}}

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Mechanics

Medium

Horizontal projection · Year 12 · 3 marks

A ball is thrown horizontally at 5.0 m s−15.0\ \mathrm{m\,s^{-1}} from a height of 1.8 m above level ground. Ignore air resistance.
  1. Calculate the horizontal distance the ball travels before it hits the ground.
    (3)
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  1. Treat vertical motion on its own: it starts with zero vertical velocity and accelerates at gg.1.81.8=12×9.81×t2{}= \tfrac{1}{2} \times 9.81 \times t^2
  2. Solve for the time of flight.t=0.606 st = 0.606\ \mathrm{s}
  3. Horizontal velocity is constant, so distance = speed × time.Distance =5.0×0.606= 5.0 \times 0.606=3.0 m{}= 3.0\ \mathrm{m}

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Mechanics

Hard

Principle of moments · Year 12 · 5 marks

Figure 1 shows a uniform plank AB of length 5 m and weight 200 N, resting on supports at its ends. A person of weight 600 N stands 2 m from A.
AB200 N600 N5 m
Figure 1
  1. (a)
    State the principle of moments.
    (1)
  2. (b)
    Find the force exerted on the plank by each support.
    (4)

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Part (a)1 mark

  1. For equilibrium, the sum of clockwise moments about any point equals the sum of anticlockwise moments.

Part (b)4 marks

  1. Moments about A eliminate R_A.RB×5R_B \times 5=200×2.5{}= 200 \times 2.5+600×2{}+ 600 \times 2
  2. RB=340 NR_B = 340\ \mathrm{N}
  3. Vertical forces balance.RA=460 NR_A = 460\ \mathrm{N}

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