Physics · Pearson Edexcel 9PH0 · Topic 4

Materials

Fluids (density, upthrust, viscosity) and solid materials (Hooke's law, stress, strain and the Young modulus).

  • 10 sub-topics
  • Taught in Year 12
  • 119 practice questions
  • 10 animated lessons
Practice questions (119) Lessons Worksheets All Edexcel Physics topics

What the specification says

Every sub-topic Pearson Edexcel can examine in this topic, with its reference number from the official specification. The Y12 and Y13 tags show when each sub-topic is usually taught.

  1. 49DensityY12
  2. 50UpthrustY12
  3. 51Viscosity and Stokes' lawY12
  4. 52CP4: Use a falling-ball method to determine the viscosity of a liquidY12
  5. 53Hooke's law and stiffnessY12
  6. 54Stress, strain and the Young modulusY12
  7. 55Force–extension and force–compression graphsY12
  8. 56Stress–strain graphs and breaking stressY12
  9. 57CP5: Determine the Young modulus of a materialY12
  10. 58Elastic strain energyY12

Try 3 questions

Easy, medium and hard questions from this topic, each with a worked solutions and the mark for every step. All 119 questions in this topic, free, no account needed.

Materials

Easy

Density · Year 12 · 3 marks

A metal block measures 2 cm × 3 cm × 2 cm and has mass 9.48 g.
  1. Calculate the density of the metal in kg m⁻³.
    (3)

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  1. 1 cm³ = 10⁻⁶ m³.VV=12 cm3{}= 12\text{ cm}^3=1.20×10−5 m3{}= 1.20 \times 10^{-5}\text{ m}^3
  2. ρ=mV\rho = \frac{m}{V}
  3. ρ=790 kg m−3\rho = 790\ \mathrm{kg\,m^{-3}}

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Materials

Medium

Upthrust · Year 12 · 5 marks

A solid block of volume 0.005 m³ and density 600 kg m⁻³ is held completely under water (density 1000 kg m⁻³).
  1. (a)
    State Archimedes' principle.
    (1)
  2. (b)
    Calculate the upthrust and the weight of the block.
    (2)
  3. (c)
    State what happens when the block is released, and find the resultant force on it.
    (2)

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Part (a)1 mark

  1. The upthrust equals the weight of fluid displaced.

Part (b)2 marks

  1. U=49.1 NU = 49.1\ \mathrm{N}
  2. W=29.4 NW = 29.4\ \mathrm{N}

Part (c)2 marks

  1. It rises to the surface and floats.
  2. F=19.6 NF = 19.6\ \mathrm{N}

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Materials

Hard

Determining viscosity · Year 12 · 6 marks

A steel ball of radius 1.5 mm (density 7800 kg m⁻³) falls at a terminal velocity of 0.05 m s⁻¹ through a liquid of density 1260 kg m⁻³.
  1. (a)
    Explain why the ball reaches a terminal velocity.
    (2)
  2. (b)
    Show that the viscosity is given by η\eta=2r2(ρs−ρl)g9v{}= \frac{2r^2(\rho_s - \rho_l)g}{9v}, and calculate it.
    (3)
  3. (c)
    Explain why the ball's speed should be measured well below the surface.
    (1)

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Part (a)2 marks

  1. The viscous drag increases with speed,
  2. until weight = upthrust + drag, so the resultant force is zero.

Part (b)3 marks

  1. 43πr3ρsg\tfrac{4}{3}\pi r^3\rho_s g=43πr3ρlg{}= \tfrac{4}{3}\pi r^3\rho_l g+6πηrv{}+ 6\pi\eta rv
  2. rearrange\text{rearrange}
  3. η=0.642 Pa s\eta = 0.642\ \mathrm{Pa\,s}

Part (c)1 mark

  1. So that it has reached terminal velocity before timing starts.

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