Further Mathematics · Pearson Edexcel 9FM0 · Option FP1 · Topic 6

Further numerical methods

Numerical methods for differential equations, such as Euler's method and its improved versions, and Simpson's rule for integrals.

  • 2 sub-topics
  • 1 in Year 12, 1 in Year 13
  • 34 practice questions
  • 2 animated lessons

What the specification says

Every sub-topic Pearson Edexcel can examine in this topic, with its reference number from the official specification. The Y12 and Y13 tags show when each sub-topic is usually taught.

  1. 6.1Numerical solution of differential equationsY12
  2. 6.2Simpson's ruleY13

Try 3 questions

Easy, medium and hard questions from this topic, each with a worked solutions and the mark for every step. All 34 questions in this topic, free, no account needed.

Further numerical methods

Easy

One step of Euler's method · Year 12 · 1 mark

  1. dydx\dfrac{\mathrm{d}y}{\mathrm{d}x}=xy{}= xy and y=2y = 2 when x=1x = 1. Using Euler's method with step length 0.2, what is the estimate of yy at x=1.2x = 1.2?
    (1)

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  1. y1=y0+h f(x0,y0)y_1 = y_0 + h\,f(x_0, y_0).A: 2.4

Total1

  • MMethod mark: for a correct method, even with a slip.
  • AAccuracy mark: for a correct answer from a correct method.
  • BIndependent mark: for a correct fact or result on its own, with no method needed.
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Further numerical methods

Not needed for Year 12Medium

Simpson's rule · Year 13 · 7 marks

II=∫121x dx{}= \displaystyle\int_{1}^{2} \frac{1}{x}\,\mathrm{d}x.
  1. (a)
    Use Simpson's rule with 6 strips to estimate I, giving your answer to 5 decimal places.
    (4)
  2. (b)
    Find the exact value of I, and hence the percentage error in your estimate.
    (3)
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Part (a)4 marks

  1. 6 strips need 7 ordinates.h=16h = \frac{1}{6}
  2. Work out every ordinate.1.00000, 0.85714, 0.75000, 0.66667, 0.60000, 0.54545, 0.500001.00000, \ 0.85714, \ 0.75000, \ 0.66667, \ 0.60000, \ 0.54545, \ 0.50000
  3. Simpson's rule.h3[y0+yn+4(odd)+2(even)]\tfrac{h}{3}\left[y_0 + y_n + 4(\text{odd}) + 2(\text{even})\right]
  4. I≈0.69317I \approx 0.69317

Part (b)3 marks

  1. I=ln⁡2I = \ln 2
  2. ∣0.69317−0.69315∣0.69315×100\frac{|0.69317 - 0.69315|}{0.69315} \times 100
  3. =0.0033%= 0.0033\%

Total7

  • MMethod mark: for a correct method, even with a slip.
  • AAccuracy mark: for a correct answer from a correct method.
  • BIndependent mark: for a correct fact or result on its own, with no method needed.
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Further numerical methods

Hard

Numerical solution of a differential equation · Year 12 · 6 marks

dydx\dfrac{\mathrm{d}y}{\mathrm{d}x}=2x+y22{}= 2x + \frac{y^2}{2}, with y=1y = 1 at x=0x = 0.
  1. (a)
    Use Euler's method with step length 0.1 to find an estimate of yy at x=0.1x = 0.1.
    (2)
  2. (b)
    Use the approximation yr+1\displaystyle y_{r + 1}≈yr−1{}\approx y_{r - 1}+2h(dydx)r{}+ 2h\left(\frac{\mathrm{d}y}{\mathrm{d}x}\right)_r with your answer to (a) to estimate yy at x=0.2x = 0.2 and at x=0.3x = 0.3, giving answers to 3 decimal places.
    (4)

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Part (a)2 marks

  1. y1y_1=y0{}= y_0+h(dydx)0{}+ h\left(\frac{\mathrm{d}y}{\mathrm{d}x}\right)_0=1+0.1×0.5{}= 1 + 0.1 \times 0.5
  2. y1=1.05y_1 = 1.05

Part (b)4 marks

  1. Use y₁ from (a).(dydx)1\left(\frac{\mathrm{d}y}{\mathrm{d}x}\right)_1=0.7512{}= 0.7512
  2. Keep the unrounded value for the next step.y2y_2=1+0.2×0.7512{}= 1 + 0.2 \times 0.7512=1.150{}= 1.150
  3. (dydx)2\left(\frac{\mathrm{d}y}{\mathrm{d}x}\right)_2=1.0615{}= 1.0615
  4. y3y_3=1.05+0.2×1.0615{}= 1.05 + 0.2 \times 1.0615=1.262{}= 1.262

Total6

  • MMethod mark: for a correct method, even with a slip.
  • AAccuracy mark: for a correct answer from a correct method.
  • BIndependent mark: for a correct fact or result on its own, with no method needed.
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