Further Mathematics · Pearson Edexcel 9FM0 · Option FM1 · Topic 2

Work, energy and power

Work done by forces, kinetic and potential energy, power, and solving problems with conservation of energy.

  • 1 sub-topic
  • Taught in Year 12
  • 17 practice questions
  • 1 animated lesson

What the specification says

Every sub-topic Pearson Edexcel can examine in this topic, with its reference number from the official specification. The Y12 and Y13 tags show when each sub-topic is usually taught.

  1. 2.1Work, energy and powerY12

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Easy, medium and hard questions from this topic, each with a worked solutions and the mark for every step. All 17 questions in this topic, free, no account needed.

Work, energy and power

Easy

Power · Year 12 · 1 mark

  1. A car's engine works at 45 kW while the car moves at 25 m s⁻¹. What is the driving force?
    (1)

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  1. P=FvP = Fv, with the power in watts.CC: 1800 N1800\ \mathrm{N}

Total1

  • MMethod mark: for a correct method, even with a slip.
  • AAccuracy mark: for a correct answer from a correct method.
  • BIndependent mark: for a correct fact or result on its own, with no method needed.
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Work, energy and power

Medium

Power and maximum speed · Year 12 · 4 marks

A car of mass 800 kg has maximum power 40 kW and resistance 600 N.
  1. (a)
    Find its maximum speed on a level road.
    (2)
  2. (b)
    Find its acceleration when moving at 33.3 m s⁻¹.
    (2)
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Part (a)2 marks

  1. PP=Fv, F{}= Fv, \ F=R at max speed{}= R \text{ at max speed}
  2. vv=40000600{}= \frac{40000}{600}=66.7 m s−1{}= 66.7\ \mathrm{m\,s^{-1}}

Part (b)2 marks

  1. F=4000033.3=1200F = \frac{40000}{33.3} = 1200
  2. aa=1200−600800{}= \frac{1200 - 600}{800}=0.75 m s−2{}= 0.75\ \mathrm{m\,s^{-2}}

Total4

  • MMethod mark: for a correct method, even with a slip.
  • AAccuracy mark: for a correct answer from a correct method.
  • BIndependent mark: for a correct fact or result on its own, with no method needed.
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Work, energy and power

Hard

Work, energy and power · Year 12 · 8 marks

A car of mass 1000 kg moves up a straight road inclined at an angle α\alpha to the horizontal, where sin⁡α=120\sin\alpha = \frac{1}{20}. The resistance to motion is constant, of magnitude 750 N, and the engine works at a constant rate of 24 kW.
  1. (a)
    Find the maximum speed of the car up the hill.
    (4)
  2. (b)
    Find the acceleration of the car when its speed is 12 m s⁻¹.
    (3)
  3. (c)
    The car reaches the top of the hill and moves onto level road, with the same resistance and power. Find its new maximum speed.
    (1)
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Part (a)4 marks

  1. At maximum speed the driving force balances resistance and the weight component.24000v\frac{24000}{v}=750{}= 750+1000×9.8×120{}+ 1000 \times 9.8 \times \frac{1}{20}
  2. v=19.4 m s−1v = 19.4\text{ m s}^{-1}

Part (b)3 marks

  1. F=maF = ma along the slope.2400012−750−490\frac{24000}{12} - 750 - 490=1000a{}= 1000a
  2. a=0.760 m s−2a = 0.760\text{ m s}^{-2}

Part (c)1 mark

  1. 24000750\frac{24000}{750}=32.0 m s−1{}= 32.0\text{ m s}^{-1}

Total8

  • MMethod mark: for a correct method, even with a slip.
  • AAccuracy mark: for a correct answer from a correct method.
  • BIndependent mark: for a correct fact or result on its own, with no method needed.
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